Elin:Spoiler/Fishing: Difference between revisions
(Add fishing land feat calculations.) |
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<pre>if (additionalFishChance >= rnd(100))</pre> | <pre>if (additionalFishChance >= rnd(100))</pre> | ||
If the random number generated by <code>rnd(100)</code> is '''50 or less''', ''' | If the random number generated by <code>rnd(100)</code> is '''50 or less''', '''numberOfFish''' will increase by 1. This means that if the random number is between '''0 and 50''' (inclusive), you will catch an additional fish, making '''numberOfFish''' increase by 1. | ||
So, '''numberOfFish''' is increased by '''1''' based on land feats, making it: | So, '''numberOfFish''' is increased by '''1''' based on land feats, making it: |
Latest revision as of 07:44, 24 November 2024
Calculations
Fish LV
The formula to calculate the fish LV that can be caught based on your fishing level:
fishLV = rnd(fishingLevel * 2) + 1
- fishingLevel: Your current fishing skill level.
- rnd: A random number between 0 and the value passed into the function.
Example
If your fishing level is 3, the potential fish LV is calculated as:
rnd(3 * 2) + 1
This gives a range of 1 to 6, meaning you can catch fish with LV between 1 and 6.
Fish LV Range Table
Fishing Level | Minimum LV | Maximum LV |
---|---|---|
1 | 1 | 2 |
2 | 1 | 4 |
3 | 1 | 6 |
4 | 1 | 8 |
5 | 1 | 10 |
6 | 1 | 12 |
7 | 1 | 14 |
8 | 1 | 16 |
9 | 1 | 18 |
10 | 1 | 20 |
11 | 1 | 22 |
12 | 1 | 24 |
13 | 1 | 26 |
14 | 1 | 28 |
15 | 1 | 30 |
16 | 1 | 32 |
17 | 1 | 34 |
18 | 1 | 36 |
19 | 1 | 38 |
20 | 1 | 40 |
Code (EA 23.37)
int num3 = EClass.rnd(num * 2) + 1;
thing = ThingGen.Create("fish", -1, num3);
Number of Fish
The formula to calculate the number of fish you can catch based on your fishing level:
numberOfFish = rnd(fishingLevel / (fishLV + 10)) + 1
- fishingLevel: Your current fishing skill level.
- fishLV: The fish LV.
- rnd: A random number between 0 and the value passed into the function.
Example
If your fishing level is 22, and the fish LV is determined to be 1, the potential number of fish is calculated as:
rnd(22 / (1 + 10)) + 1
This simplifies to:
rnd(22 / 11) + 1
The rnd(2)
generates a random number between 0 and 1. Adding 1 ensures that you will catch at least 1 fish, and the number of fish can either be 1 or 2, depending on the random result.
Adding Land Feats
The initial chance of catching extra fish starts at 5%.
If the land feats include Beach (3604) and Fishing Spot (3706), these feats will contribute additional chances to the base chance.
For example:
- Beach (3604) adds 20% to the base chance.
- Fishing Spot (3706) adds 25% to the base chance.
Starting with a 5% chance, the total chance is calculated using the following code:
additionalFishChance = 5 additionalFishChance += isBeach * 20 + isFishingSpot * 25
Where:
- isBeach is a flag (either 0 or 1) indicating whether the land feat is a Beach (3604).
- isFishingSpot is a flag (either 0 or 1) indicating whether the land feat is a Fishing Spot (3706).
If both features are present (i.e., both flags are set to 1), then:
additionalFishChance = 5 + 1 * 20 + 1 * 25 = 50
Checking the Chance to Increase the Number of Fish
The additionalFishChance value is then compared to a random number generated by the rnd(100)
function. The value of rnd(100)
generates a random number between 0 and 99 (inclusive).
If the value of additionalFishChance is greater than or equal to the random number, the number of fish will increase by 1.
This check is done with:
if (additionalFishChance >= rnd(100))
- If the random number generated by
rnd(100)
is 50 or less, the number of fish will increase by 1. - If the random number is greater than 50, the number of fish will remain the same.
Thus, the probability of increasing the number of fish is 50% (because additionalFishChance = 50 ).
Example with Land Feats
Let's say your fishing level is 22, and the fish LV is 1. You calculate the base number of fish as:
numberOfFish = rnd(22 / (1 + 10)) + 1 = rnd(2) + 1
Thus, you could catch 1 or 2 fish, based on the random result.
Now, you evaluate the land feats:
- Starting with additionalFishChance = 5 (the base chance).
- If the land feats are present:
* Beach (3604) adds 20 to additionalFishChance. * Fishing Spot (3706) adds 25 to additionalFishChance.
So, the new additionalFishChance becomes:
additionalFishChance = 5 + 20 + 25 = 50
Next, the random chance is checked:
if (additionalFishChance >= rnd(100))
If the random number generated by rnd(100)
is 50 or less, numberOfFish will increase by 1. This means that if the random number is between 0 and 50 (inclusive), you will catch an additional fish, making numberOfFish increase by 1.
So, numberOfFish is increased by 1 based on land feats, making it:
- numberOfFish = numberOfFish + 1 (if the random check passes).
- If the random number exceeds 50, numberOfFish remains the same.
Number of Fish Table
Fish LV | Minimum Fishing Level for 2 Fish | Minimum Fishing Level for 3 Fish |
---|---|---|
1 | 22 | 33 |
5 | 30 | 45 |
10 | 40 | 60 |
15 | 50 | 75 |
20 | 60 | 90 |
25 | 70 | 105 |
30 | 80 | 120 |
35 | 90 | 135 |
40 | 100 | 150 |
Code (EA 23.37)
num2 = EClass.rnd(num / (num3 + 10)) + 1;
int num4 = 5;
if (EClass.Branch != null)
{
num4 += EClass.Branch.Evalue(3604) * 20 + EClass.Branch.Evalue(3706) * 25;
}
if (num4 >= EClass.rnd(100))
{
num2++;
}
if (thing != null)
{
thing.SetNum(num2);
thing.SetBlessedState(BlessedState.Normal);
}